Solve square root problems

Introduction :
The Square root problems of numbers are done when the number is multiplied through itself. In the same way for polynomial the square root is obtained when the polynomials are multiplied by it.

              It is credible for solve together positive and negative numbers but when a negative number is taken out of root the value will become invented. There are two types of square problems such as ideal squares and non perfect square. It is simple to solve square root for perfect square.

Methods for Solving Square Root Problems:

The easiest method to define Square root problems in the method by using Prime Factorization:

(i) Write down the prime factorization of n from the given problems. Pair the factors such that primes in each pairs are equal.

(ii) Select one prime from every one couple and resolve multiplication of all such primes.

(iii) The multiplication obtained in (ii) is the square root of n problems.

These methods are used to solve the square root problems as easiest way.

Properties of Square Root Numbers:

If the unit’s digit of a number is 2, 3, 7 or 8, then it is not a perfect square and hence doesn’t have a square root.
If a number have square root mean it should have the numeral values of 0, 1,4,5,9.
Which are the odd numbers ends with of zeros mean it should not have a square root.
If a number ends in an odd number of zeros, then it doesn’t have a square root. If a square numeral is followed by an even number of zeros, it has a square root.
Solve Square Root Problems-example:

Perfect Squares:

Solve the square root of the following problems:

(a).v1600 = v2*v2*v5*v5*v4*v4.

According to the method, choose one prime from each pair

                 = 2*5*4.

                 = 40

So the perfect square root is 40.

(b).v900 = v3*v3*v5*v5*v2*v2.

According to the method, choose one prime from each pair,

                  = 3*5*2.

So the perfect square root is 30.

(c).v144 = v2*v2*v2*v2*v3*v3

According to the method, choose one prime from each pair,

                = v4*v4*v3

                =12.

So the solution is 12.

Non Perfect Squares:

Solve the square root of the following:

(a).v2352 = v2*v2*v2*v2*v3*v7*v7

According to the method, choose prime from each pair

                  = v4*v4*7*v3

According to the method, choose 4 as a prime from each pair

                   = 4*7*v3

                   =28*v3

So the square root of v2352 = 28*v3.

(b).v603 = v3*v3*v67

                =3*v67

So, the square root of v603 = 3*v67.

(c).v9408 =v 2*v2*v2*v2*v2*v2*v3*v7*v7

                   =2*2*2*7*v3.

                  =4*2*7*v3

                  =56*3.

So the square root of v9408= 56*3.

I like to share this what is a algebraic expression with you all through my article.