Number Series Solver

Number series solving is needed some logical thinking
Learn now number series by solving  some examples

EX:1       1,3,5,X,9,11 THAN WHAT IS X?

Whenever you solve the number series first just absurb the pattern
Here pattern is looking like odd number series
The odd number series after 5 and before 9 we will get 7.
Here missing number from the series is 7. x=7 is the answer

EX:2    2,4,6,8,__,12,14

We observe the above series it's an  even number series
Number we have to find is followed by 8 and preceded by 12.The next even number to 8 is 10 

EX:3     1,3,5,7,9,__,13,15

We observe the above series all terms are even number

Number we have to find is followed by 9 and preceded by 13, so the next odd number to 9 is 11 

EX:4   3,6,9,4,8,12,5,10,___

Here if we first observe the first three terms are 3x1,3x2,3x3

than next three terms in the series are 4,8,12 so we can write them as 4x1,4x2,4x3.

So next three terms in the series will be 5x1,5x2,5x3 (5,10,15) , answer is 15

EX:5  1,2,4,7,11,__,22,29

The difference between second and first term is 2-1=1
Difference between third and second term is  4-2=2
Difference between fourth and third term is 7-4=3
Difference between fifth and fourth term is 11-7=4
Here we observes that the differences between two successive terms are increased by 1
let us assume next term to the 11 as x so difference between x and 11 will be x-11=4+1=5 =>x-11=5
x-11+11=5+11
x=16
Lets check  16 (the answer for this series) is satisfying the pattern or not
22-16=6
29-22=7
so pattern is satisfied with 16

EX:6 1,5,9,13,__,21

we observe the pattern here the difference between two successive terms is equal to 4 like
5-1=4 , 9-5 =4 ,13-9=4, so the numbers in the series  are in the  arthematic progression
Now assume the required number as x so x-13=4, so x-13+13=4+13
x=17

EX:7 1,2,4,8,16,__,64

We observe here  second term is equal to first term X 2,Third term is equal to second term X  2, fourth term is equal to third term  X  2 and so on .....
The required sixth term which is equal to fifth term x 2
sixth term=16 x 2= 32

Ex:8 1,4,9,16,__,36

Here the  first term is 1 which can be written as =1^2, second term 4 which can be written as 2^2
Third term is 9 which can be written as 3^2, fourth term is 16 which can be written as 4^2
The  fifth term will be 5^2 =25

EX:9: 1,8,27,64,__,216

Here first term is 1 which is equal to 1^3, second term is 8 which can be written as 2^3,third term is 27 which can be written as 3^3, fourth term is 64 which can be written as 4^3,so fifth term will be 5^3 so 125
Now check the pattern sixth term is equal to 6^3=216

EX:10: 0,1,8,27,__,125,216

Here we observe the pattern
First term is equal to (1-1)^3=0,second term is equal to (2-1)^3=1^3=1,third term is equal to (3-1)^3=2^3=8,forth term is equal to (4-1)^3=3^3=27.
Fifth term is equal to (5-1)^3=4^3 = 64
Lets check the pattern, sixth term is equal to (6-1)^3=5^3=125
seventh term is equal to (7-1)^3=6^3=216

Now Try this Example :2,5,8,11,x,17 on Number Series Solver

Examples on number series for practice:

Now after observing  the series the common difference between two successive elements is (5-2)=3=(8-5), so common difference is 3

The given series is in arithmetic progression, so the next element to the 11 is 11+3=14

so x=14 is the missing number of the series

More Examples on Number Series Solver

Ex Find 1,2,4,8,x,32 so x=?

Solution :Here common ratio between two successive terms is 2/1 =4/2=8/4=2

 the series is in geometric progression,  (x/8) = (8/4)

so x/8=2,  x=8 *2

x=16, so x=16 is the missing number of the series.

Some more examples for practice:

problem 1)   1,16,81,__,625?   tip:1^4,2^4,3^4,4^4,5^4

problem 2) 11,15,19,12,16,20,13,17,__ ?  observe first three terms than next three than next three and than compare you will get the answer

problem 3) 0,1,1,2,3,5,8,__,21............ tip third term=first term+second term

problem 4)0,2,6,12,20, __ .................. tip n^2-n for first term n=1 for second term n=2 and so on

problem 5)7,14,21,28,__  ...................tip series in multiples of 7 or in geometric progression

problem 6) abc , bcd, def , ____       no tip for this , it's a simple question